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Wednesday, December 31, 2014

Formulas for the Determination of Yarn Count

The system by which we determine the yarn number is called count. Count is the number of yarn denoting the sophistication or obesity of yarn. So by linear density or the yarn count, we can know how fine or course the yarn is. It indicates the mass per unit length or length per unit mass of yarn. 

Yarn Count
 
          The length of the sample X Weight unit
-         Indirect count system = ………………………………………………

           The weight of the sample X Length unit
 
From the above formula, the count in different indirect systems is as follows –
      Sample yarn length (yds) X 1 lb
1.     English cotton count (Ne) = ………………………………………………
Sample yarn weight (lb) X 840 yds
                                                                  Sample yarn length (m) X 1 kg
2.     Metric count (Nm) = ………………………………………………
   Sample yarn weight (kg) X 1000 m
                                       Sample length (m) X 0.5 kg
3.     French or Continental count (Nf) = …………………………………………
       Sample weight (kg) X 1000 m
                                                                   Sample length (yds) X 1 lb
4.     Worsted count (w) = ………………………………………………
      Sample weight (lb) X Weight unit

                       Sample yarn weight X length unit
-         Direct count system = ……………………………………………
                      Sample yarn length X Weight unit
 
From the above formula, the count in different direct systems is as follows –
         Sample yarn weight (gm) X 1000 m
1.     Tex count = ……………………………………………………
     Sample yarn length (m) X 1 gm
                                                             Sample weight (gm) X 9000 m
2.     Denier count = ………………………………………………
     Sample length (m) X 1 gm
                                                                                 Sample weight (lb) X 14400 yds
3.     Linen/Hemp/Jute count = …………………………………………………
       Sample length (yds) X 1 lb

     Conversion of count from one count to another

1.     Denier to cotton:
English cotton count = 5315/Yarn count in denier system
2.     Denier to Tex:
Tex count = Count in denier system/9
3.     English to Tex:
Tex count = 590.5/English count
4.     English to denier:
Denier count = 5315/English count
5.     Cotton to metric:
Metric count = English cotton count X 1693
6.     Tex to denier:
Denier = Tex X 9

     Resultant count of yarn (For same count of yarn)

1.     Resultant count of indirect system = Count of single yarn/No. of doubling or ply
2.     Resultant count of direct system = Count of single yarn X No. of doubling or ply

     Resultant count of yarn (For different count of yarn)

1.     Resultant count of indirect system = 1/Sum of the weight of folded yarn’s length unit
2.     Resultant count of direct system = Sum of the weight of folded yarn’s length unit

Mathematical problems and solution of yarn count

1.     Find out the cotton count if weight of 8400 yds yarn is 1 lb.
Solution:
We know,
      Length (yds)                 1 lb
            English cotton count =…………………….. X …………………
                                                                 840 (yds)                      Weight (lb)
                                                            8400 yds                            1 lb
                                                   = ……………………… X …………………… = 10 S (ANS).
                                                            840 yds                              1 lb
 
2.     If 120 yds cotton yarn having 25 grain weight then what will be the count?
Solution:
                                                      Yarn length (yds)                    1 lb      
English cotton count = ……………………………. X ……………………….
                                                          840 yds                               Yarn weight (lb)
                                        = 120/840 X 1/(25/7000) = 120/840 X 7000/25
                                        = 40S (ANS).
 
3.     If 1000m Nylon yarn having 1.67gm weight then what will be the Denier?
Solution:
We know,
                                        Yarn wt. (lb)                           14400 yds
            Jute count = ……………………….. X ………………………
                                               1 lb                                   Yarn length (yds)
                                          3/16                    14400 yds
                                = ……………… X ………………….
                                          1 lb                       100 yds
                                = 3/16 X 14400/100 = 27 lb/Spindle (ANS).
 
4.     Find out the metric count if weight of the 400m yarn is 40gm.
Solution:
We know,
                                               Length (m)                     1 kg   
            Metric count = …………………….. X …………………
                                                1000 m                          Weight (m)
                                    = 400m/1000m X 1kg/(4kg/1000) = 10S (ANS).
 
5.     Find out the worsted count if the weight of 80 yds is 50 grain.
Solution:
We know that,
                                                Length (yds)                  1 lb
            Worsted count = ……………………… X …………………
                                                   560 yds                          Weight (lb)
                                                    80 yds                              1 lb
                                         = …………………… X …………………….
                                                   560 yds                            50/7000 lb
                                        = 20S (ANS).
 
6.     A trading corporation provides you a 24.3 Ne yarn, Find out the Tex and denier of that yarn.
Solution:
Given,
            Wk = 1 lb = 453.6 gm
            Wr = 1 gm
            Ik = 840 yds = 840 X 0.9144 m
            Ir = 1000 m
We know,
                        1                     Wk/Wr
            Nr = ………… X ………………
                        Nk                     Ik/Ir
                                        1                                     453.6/1
Tex = ……………. X …………………………………..
                        24.3                         (840 X 0.9144)/1000
       = 24.3 Tex (ANS).
Again,
            We know denier = 9 X Tex
                                            = 9 X 24.3 Tex = 218.7 denier (ANS).

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About the Author :

He is Md. Abu Sayed from Naogaon, Bangladesh. He is a Textile Engineer and working as a Testing Engineer at Bureau Veritas CPS (BD) Ltd. He also Likes article writing on Textile and Clothing Technology.

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8 comments:

  1. Dear Abu, thanks for this interesting blog. Will use whenever I need specific information, cheers from Germany, Heike

    ReplyDelete
    Replies
    1. You are most welcome Dear. Thanks for your sweet comment.

      Delete
  2. Count =30 & 40
    Resultant count =?
    Plz describe it

    ReplyDelete
  3. For 30 count, wt. of 1 hank yarn = 1/30 lbs
    and for 40 count, wt of 1 hank yarn = 1/40 lbs
    So, the resultant count = {1/ (1/30+ 1/40)} = 17.14 S

    ReplyDelete
  4. 840 yard=770 m=1 Lea=120 yard=0.45kg
    1 Hank = 120 yard
    Then we will do calculate number of hank *120 yard

    ReplyDelete
  5. 1 Hank = 120 yard
    Total number of hank multiple from 120 yard
    840 yard = 770 m= 120 Yard= 110 m
    110m = 0.45 kg

    ReplyDelete